RE: Optimization

> Thanks to Joerg Heinicke, I managed to pass the position of
> the B element to the C elements. Further, I now need a globally
> unique number for C. For that, I've been using (within C):
>
> select="count(../preceding-sibling::B/C)+position()"
>
count(../preceding-sibling::B/C) is constant for all the C's within one B,
so pass it to the C template as a parameter. (But isn't it the same as the
position() of the B, which you were passing anyway?)

Mike Kay


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list