Cart
|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Optimization
 Once again the structure is <A> <B><C/><C/>...<C/></B> <B><C/><C/>...<C/></B> . . </A> Thanks to Joerg Heinicke, I managed to pass the position of the B element to the C elements. Further, I now need a globally unique number for C. For that, I've been using (within C): select="count(../preceding-sibling::B/C)+position()" But this seems very inefficient, and it looks like performance degrades over time (may be an implementation issue?). Any hints on a less costly (constant time perhaps) way of getting enumerated the C elements? Thanks, Morten XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! 
Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|
