There is no direct expression for this, but you can accomplish
the same thing using a recursive template. 

<?xml version="1.0"?>
<xsl:stylesheet 
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   version="1.0"
>
<xsl:preserve-space elements="*"/>
<xsl:output method="text"/>

<xsl:template match="/">
 <xsl:call-template name="loop">
  <xsl:with-param name="repeat" select="number(10)"/>
 </xsl:call-template>
</xsl:template>

<xsl:template name="loop">
 <xsl:param name="repeat">0</xsl:param>
 <xsl:if test="number($repeat) >= 1">
Loop Iteration # <xsl:value-of select="$repeat"/>
  <xsl:call-template name="loop">
   <xsl:with-param name="repeat" select="$repeat - 1"/>
  </xsl:call-template>
 </xsl:if>
</xsl:template>

</xsl:stylesheet>

You may want to consider why you want a loop though. 
Often, there is a structure in your input that can be
used to drive the output, and for that you just need 
an XPath. 

Charly wrote:
> 
> Hello,
> does anyone knows how to make a loop for in xsl.
> Something more like .
> 
>    <xsl:loop name="i" from="1" to="10" step="1">
>       $i
>    </xsl:loop>
> 
> Please help
> 
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

--
Mitch.Amiano (@alcatel.com)
SW Development Engineer in C++/Java/Perl/TCL/SQL/XML/XSLT/XPath
Advance Design Process Group, Raleigh Engineering Services     Alcatel
USA

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list