RE: Displaying entries in a table vertically

When displaying entries horizontally, you do

<xsl:for-each select="item[position() mod $n = 1]">
  <xsl:for-each select=". | following-sibling::item[position() &lt; $n]"

For a vertical display, you just need to change the selection conditions to
something like

<xsl:for-each select="item[position() &lt;= $n]"
  <xsl:for-each select=". | following-sibling::item[position() mod $n = 0]">

Not tested and may need minor adjustment.

> -----Original Message-----
> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of Alan Alda
> Sent: 17 July 2001 22:36
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Displaying entries in a table vertically
>
>
> Hi,
>
> I am writing an XSL sheet which produces an HTML table
> using some entries (which are sorted by my XSL before
> displaying) of an XML file. Pretty straightforward...
>
> The problem is that the specifications doc. that I
> have, requires me to display the entries in the table
> sorted in a vertical fashion.
>
> This means that the spec. requires the entries to be
> like:
> A P U
> B Q V
> C R
>
> whereas, since I am outputting the entries row-wise, I
> am getting the output:
> A B C
> P Q R
> U V
>
> Is there any way I can display the entries sorted in a
> vertical fashion in the table using my XSL sheet?
>
> Thanks,
> Cheers,
> Alan.
>
>
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