RE: Conditional variable assignment with node-set as v

>   I uses Saxon6.0.2 as XSLT processor.

Upgrade! The current version is 6.4.3.

>   I currently have a need to use conditional variable
> assignment with node-set as value.  I tried to use
> saxon:node-set, but still gets the error:

I suspect the error is from the way you are using this variable, not from
the way you are setting it up. Within this xsl:variable, the two calls on
saxon:node-set() seem to be unnecessary: it's never necessary to call
saxon:node-set on something that is already a node-set, which both these
expressions are.

I'm afraid I don't know quite what you mean by conditional variable
assigment. Have you considered the syntax:

<xsl:variable name="v" select="$ns1[$condition] | $ns2[not($condition)]"/>

Mike Kay
Software AG

> At XSLT 1.0, conversion of a result tree fragment to a
> node-set is not allowed.
>   My XSLT code looks like:
> <xsl:variable name="extended-attrs-bid">
> <xsl:choose>
> <xsl:when
> test="normalize-space(RFQDomainAttributeDefinition)">
> <xsl:value-of
> select="saxon:node-set(RFQDomainAttributeDefinition[@Domain
> = 'lbid']/ExtendedAttributeDefinition)" />
> </xsl:when>
> <xsl:otherwise>
> <xsl:value-of
> select="saxon:node-set(Bid/ExtendedAttribute[generate-id()
> = generate-id(key('extended-attrs-bid-index',
> @ExtendedAttributeCode))])" />
> </xsl:otherwise>
> </xsl:choose>
> </xsl:variable>
>   How to conditionally assign the node-set value I
> needed?
>
> Much thanks,
> Xiaocun
>
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