changing the order of xml elements when doing XSLT

hi all..

i have a need to accomplish the following.. i.e. when doing an XSLT over an
XML file.. have the output xml be in a specific order that is NOT the same
as the order in the original XML. i guess it can only be done in the xsl
file somehow.. if at all possible.. but i couldn't figure it out.

to clarify what i mean.. here's an example:

source.xml

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="mapper.xsl"?>
<record>
<a>1</a>
<b>2</b>
<c>3</c>
</record>

mapper.xsl

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format">
  <xsl:output method="xml" omit-xml-declaration="yes" indent="no"/>
        <xsl:template match="/">
                <xsl:apply-templates/>
        </xsl:template>
        <xsl:template match="record">
	       	<newrecord><xsl:apply-templates/></newrecord>
	</xsl:template>
	<xsl:template match="c">
		<CC>
			<xsl:value-of select="."/>
		</CC>
	</xsl:template>
	<xsl:template match="a">
		<AA><xsl:value-of select="."/></AA>
	</xsl:template>
	<xsl:template match="b">
			<BB>
			<xsl:value-of select="."/>
		</BB>
	</xsl:template>
</xsl:stylesheet>

current output:

<newrecord
xmlns:fo="http://www.w3.org/1999/XSL/Format"><AA>1</AA><BB>2</BB><CC>3</CC><
/newrecord>

desired output:

<newrecord
xmlns:fo="http://www.w3.org/1999/XSL/Format"><CC>3</CC><BB>2</BB><AA>1</AA><
/newrecord>

any ideas would be highly appreciated..

thanks!

Charlie


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