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Re: Not So Newbie XPath Question

Subject: Re: Not So Newbie XPath Question
From: Bernard Harrison <b_harrison@xxxxxxxxxxxxx>
Date: Tue, 20 Feb 2001 01:49:22 +1100
bernard harrison
DPawson@xxxxxxxxxxx wrote:
> 
> <?xml version = '1.0' encoding = 'utf-8'?>
> <!DOCTYPE xsl:stylesheeet
> [
> <!ENTITY nl "<xsl:text>&#x0A;&#xD;</xsl:text>">]>
> 
> <xsl:stylesheet version='1.0'
> xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
> xmlns:saxon="http://icl.com/saxon"
> >
> 
>   <xsl:output method="text"/>
> 
> 
> <xsl:template match="/">
>   <xsl:apply-templates/>
> </xsl:template>
> 
> <xsl:template match="z[a]">
>   <xsl:if test="a">
>     <xsl:apply-templates select="a"/>
>   </xsl:if>
> 
> </xsl:template>
> 
> <xsl:template match="a[not(following-sibling::a)]" >
>   <xsl:value-of select="name(following-sibling::*[1])"/>
> </xsl:template>
> 
> </xsl:stylesheet>
> I'm sure it could be simplified.
> hth DaveP

Mmm. Does using following-sibling work given Jeni Tennison's Post?

Jeni Tennison wrote:
> This will only work in a select expression because match patterns
> don't allow following-sibling:: axes.  For a match pattern, you need
> something like you have already or one of its equivalents, like:

Bern

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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