Re: Not So Newbie XPath Question
> Mmm. Does using following-sibling work given Jeni Tennison's Post? you can use any XPath expression inside a  predicate. The axis restriction only applies to step construction. so you can't do match="a/following-sibling::b]" but you can do match="b[preceding-sibling::a] which matches what was intended, a b with an earlier a sibling. (However I don't think Dave's stylesheet is doing quite what you asked for) David _____________________________________________________________________ This message has been checked for all known viruses by Star Internet delivered through the MessageLabs Virus Control Centre. For further information visit http://www.star.net.uk/stats.asp XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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