Absolute ordering -- determining order when position() won't

Hello,

I have XML which consists of elements which are either folders or files:
 
<Folder name="foldera">
   <File name="a" />
   <Folder name="folderb">
   </ Folder>
   <File name="b" />
   <Folder name="folderc">
      <File name="c" />
      <File name="d" />
   </ Folder>
</Folder>
 
The order of the folders and files is arbitrary. I have written some XML to
list the names of all of the files:
 
<xsl:template name="files_folders">		
   <xsl:choose>
      <xsl:when test="self::File">				
         <xsl:call-template name="files" />
      </xsl:when>
      <xsl:when test="self::Folder">			
          <xsl:for-each select="./*">					
             <xsl:call-template name="files_folders" />

          </xsl:for-each>		
      </xsl:when>
   </xsl:choose>		
</xsl:template>
 
<xsl:template name="files">		
   <h3>
      <xsl:value-of select="@name" />
   </h3>
</xsl:template>
 
What I would like to do, is precede each file name with a number, like so:
 1 a
 2 b
 3 c
 4 d
 
If I use position(), then I will get the order of the element in the
subtree:
 1 a
 3 b
 1 c
 2 d	
 
Does anyone have any idea how to solve this problem?
Thanks,
Ross


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