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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] mapping attributes.
 I'm sure this is a common task, but I can't seem to find a simple answer.
I have an XML document, like so:
<DOCUMENT>
<SECTION ID="SOME_ID">
<TITLE>This sections title</TITLE>
<BODY />
<RELATED ID="ANOTHER" />
</SECTION>
<SECTION ID="ANOTHER">
<TITLE>Another sections title</TITLE>
<BODY />
<RELATED ID="SOME_OTHER" />
</SECTION>
</DOCUMENT>
For each section, I want to produce a cross reference to related sections,
like so:
See Also:
<A HREF="#ANOTHER">Another sections title</A>
The "#ANOTHER" is easy to get, but the link text isn't. This works:
<xsl:for-each select="SECTION[@ID='ANOTHER']/TITLE">
But, that involves hard-coding 'ANOTHER' in the XSL. (unacceptable) What I
want is:
<xsl:for-each select="SECTION[@ID={RELATED/@ID}]/TITLE"> but it doesn't find
anything.
Where the RELATED's ID is a "join" on SECTION's ID. Is this possible?
Jamie
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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