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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: mapping attributes.
 I think I understand what you want, but the code you're showing
doesn't seem to match. What I think you want is to generate
the cross-reference where the <RELATED> element occurs and have the
generated link contain the text of the title for the targeted
SECTION (based on matching the value of the ID attributes).
If that is what you want, something like this ought to work:
<xsl:template match="RELATED">
<xsl:variable name="target" select="@ID"/>
<A HREF="#{@ID}>
<xsl:value-of select="//SECTION[@ID=$target]/TITLE"/>
</A>
</xsl:template>
Sara
> -----Original Message-----
> From: Jamie [mailto:jamie@xxxxxxxxxx]
> Sent: Monday, November 06, 2000 3:13 PM
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: mapping attributes.
>
>
> I'm sure this is a common task, but I can't seem to find a
> simple answer.
>
> I have an XML document, like so:
>
> <DOCUMENT>
> <SECTION ID="SOME_ID">
> <TITLE>This sections title</TITLE>
> <BODY />
> <RELATED ID="ANOTHER" />
> </SECTION>
> <SECTION ID="ANOTHER">
> <TITLE>Another sections title</TITLE>
> <BODY />
> <RELATED ID="SOME_OTHER" />
> </SECTION>
> </DOCUMENT>
>
> For each section, I want to produce a cross reference to
> related sections,
> like so:
>
> See Also:
> <A HREF="#ANOTHER">Another sections title</A>
>
>
> The "#ANOTHER" is easy to get, but the link text isn't. This works:
>
> <xsl:for-each select="SECTION[@ID='ANOTHER']/TITLE">
>
> But, that involves hard-coding 'ANOTHER' in the XSL.
> (unacceptable) What I
> want is:
>
> <xsl:for-each select="SECTION[@ID={RELATED/@ID}]/TITLE"> but
> it doesn't find
> anything.
>
> Where the RELATED's ID is a "join" on SECTION's ID. Is this possible?
>
> Jamie
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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