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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] outputting the "position()" of parent
How do I output the posistion of the parent. I can output the position of the current node like this: <xsl:value-of select="position()"/> So I thought I could do this: <xsl:value-of select="../position()"/> but it doesn't work.... any suggestions? thanks in advance Justin XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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