Re: outputting the "position()" of parent

Justin Friedl wrote:
> 
> How do I output the posistion of the parent.  I can output the position of
> the current node like this:
> <xsl:value-of select="position()"/>
> 
> So I thought I could do this:
> <xsl:value-of select="../position()"/>
> but it doesn't work.... any suggestions?
> 

David Carlisle (whom I trust is home by now!) came up with the solution
to this:

xml:
<?xml version="1.0"?>
<root>
  <a></a>
  <a></a>
  <a></a>
  <a></a>
  <a><b/></a>
  <a></a>
  <a></a>
</root>

xsl:
<?xml version="1.0"?>
<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
  <xsl:template match="b">
    <result>
      <xsl:text>b's parent is in position </xsl:text>
      <xsl:value-of select="count(../preceding-sibling::*)+1" />
    </result>
  </xsl:template>
</xsl:stylesheet>

result (saxon):
<?xml version="1.0" encoding="utf-8" ?><result>b&#39;s parent is in
position 5</result>

Francis.


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list