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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] testing for last node in a list
Hello,
I am generating a list of ancestor nodes for a matched CLASS element. The XSL
calls this template to output the ancestors when a CLASS is matched. I want to
output a "|" character after each CLASS node, EXCEPT the last one. I am unable
to express the correct test for the last node in this list. I tried using
<xsl:if test="position()=last()">, but this statement returns true each time the
template is called.
Is there another way to solve this?
Thanks,
Ann Marie
My XSL:
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<!-- named template to do the hierarchy tracing -->
<xsl:template match="CLASS" mode="hierarchy">
<xsl:apply-templates select="key('classes', @SUPERCLASS)" mode="hierarchy"/>
<br data="{@SUPERCLASS}"><a href="{@NAME}.html"><xsl:value-of
select="@NAME"/></a></br>
<xsl:if test="position()=last()">
<xsl:text>|</xsl:text>
</xsl:if>
</xsl:template>
Output:
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CIM_ManagedSystemElement
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CIM_LogicalElement
|
CIM_SoftwareElement
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Solaris_Package
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XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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