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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: selecting a node without its children
You can use @id to get the attribute value in ur XSL like this
<xsl:template match="/">
<xsl:for-each select="STORY">
<xsl:for-each select="AUTHOR">
<xsl:value-of select="@id"/>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
Francis
> -----Original Message-----
> From: Ben Sorek [mailto:bsorek@xxxxxxxxxxxxx]
> Sent: Thursday, March 30, 2000 6:39 PM
> To: xsl-list@xxxxxxxxxxxxxxxx
> Subject: RE: selecting a node without its children
>
>
> This is my XML
>
> <STORY>
> <AUTHOR id="xsw">Stephen King</AUTHOR>
> </STORY>
>
> If I have a template
>
> <xsl:template match="STORY">
> ....
> </xsl:template>
>
> how can i get the id attribute of author inside that template?
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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