Setting the value of the HREF attribute

Dear XSL-ers

To become familiar with XML & XSL, I am in the process of representing a
web site using these technologies. I have just reached a bit of a hurdle
and wondered if you guys could offer some advice....

Below is a fragment from a xml document which states Philips Research as
a "participant". I want to use XSL to set produce a HTML page that
includes a link to the Philips Research www site. My problem is that i
don't know how to set the value of the HTML's HREF attribute to the
specified URL.

I have also included a fragment of the XSL style sheet which is to
format the xml into html. If someone could offer a solution to my
problem, that would be great.

Thanks

Nigel

>>>>> Fragment of XML document

<?xml version="1.0" encoding="UTF-8"?>
<participants>
  <participant link="http://www.research.philips.com">Philips Research
(UK)</participant>
 </participants>

>>>>>>>>> Fragment of XSL Stylesheet

<xsl:template match="participants">
  <xsl:for-each select="participant">
    <!-- set the HREF attribute to the value of @link -->
    <!-- this doesn't work: -->
    <!-- <A HREF="<xsl:value-of select="@link"/>">click here</A> -->
   <xsl:apply-templates/>
  </xsl:for-each>
</xsl:template>

--
      Nigel Byrnes

                               "We continue..." Pete Tong

Software Engineering and Applications Group,
Philips Research Labs,
Redhill.                           Tel: +44 (0)1293 815578
RH1 5HA.                           Fax: +44 (0)1293 815024
UK.                                GSM: +44 (0)7899 940391
                    Email: byrnes@xxxxxxxxxxxxxxxxxxxxxxxx



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