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Original Message From: "G. Ken Holman" > At 2010-10-28 14:32 +0100, Pete Cordell wrote: >>Hi David, >> >>It should be ns1:root/a/b/ns2:root/b as Philip says because in the scheme >>I described a and b were unqualified. As such there's no difference in >>name between b in ns1 and b in ns2 as there would be if they were >>qualified. >> >>I think Philip is right about the issues. It's down to the limitations in >>XPath expressibility. You need to say something like: b whose qualified >>parent is in namespace ns1. Sort of b[qualified-parent-ns()=ns1]! > > b[parent::ns1:*] > > ... or if you are matching nodes: > > ns1:*/b My XPath knowledge is very weak, but does that allow for matching 'b' in the 'tree' of: ns1:root/a/b ? I had guessed that ns1:*//b might be better, but I think that expression would match both 'b's in the Philip's 'tree' of: ns1:root/a/b/ns2:root/b Yours confused, Pete Cordell Codalogic Ltd Interface XML to C++ the easy way using C++ XML data binding to convert XSD schemas to C++ classes. Visit http://codalogic.com/lmx/ or http://www.xml2cpp.com for more info
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