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Re: XSL Running total help

• To: xml-dev@l...
• Subject: Re: XSL Running total help
• From: "John L. Clark" <jlc6@p...>
• Date: Thu, 21 Oct 2004 14:24:36 -0700
• In-reply-to: <59096c020410211342d84da49@m...>
• References: <59096c020410211342d84da49@m...>
• Reply-to: "John L. Clark" <jclark@n...>
• User-agent: Mutt/1.5.6i

On Thu, Oct 21, 2004 at 01:42:48PM -0700, Ryan Ness wrote:
> Here's my XML snip:
> 

<snip/>

> What I need is to display the largest 8 weight values (in a text file)
> and then instead of continuing to display the remaining assetWeights,
> I want to add them up, and display the total...

It looks like you have the first 8 values, and just want help with the
total.  I did it with this line:

    <xsl:value-of select="sum(assetWeights[position() &gt;
        8]/@weight)"/>

Obviously, in the context of the <snip/> root.  You'd have to rewrite it
slightly to work in your for-each block, but I think you should ditch
the for-each and work directly from templates called from the parent so
as to (easily) avoid the repetition across every child with position
greater than 8.

Here's my full test stylesheet:

    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
                    version="1.0">
        <xsl:output method="text"/>

        <xsl:template match="/snip">
            <xsl:value-of select="sum(assetWeights[position() 
                &gt; 8]/@weight)"/>
        </xsl:template>
    </xsl:stylesheet>

Which returns 0.727.  Also obviously, I'm temporarily ignoring the
sorting requirement, but your code looks like it already takes care of
that.

Take care,

    John L. Clark

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• References:
  • XSL Running total help
    • From: Ryan Ness <ryan.ness@g...>

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