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RE: Parsing numbers in Scientific Notation

• To: "'Nicholas Shanks'" <contact@n...>,<xml-dev@l...>
• Subject: RE: Parsing numbers in Scientific Notation
• From: "Michael Kay" <michael.h.kay@n...>
• Date: Fri, 7 May 2004 09:27:21 +0100
• In-reply-to: <5E67AF7E-9DC4-11D8-A5D3-0005020F149E@n...>
• Thread-index: AcQx0h85J4RiY6PRTueae8eVcd3OSgCOgxUg

If it's any use to you, XSLT 2.0 (and therefore Saxon 7.x) support numbers
in scientific notation (or at any rate, in Fortran notation - 1.0e30).

In an XSLT 1.0 product that supports calls to Java, for example Saxon 6.x,
it's easy enough to do via an extension function. In Saxon:

<xsl:variable name="v" select="Double:parseDouble('1.0e30')"
                       xmlns:Double="java:java.lang.Double"/>

Michael Kay 

> -----Original Message-----
> From: Nicholas Shanks [mailto:contact@n...] 
> Sent: 04 May 2004 12:13
> To: xml-dev@l...
> Subject:  Parsing numbers in Scientific Notation
> 
> Hey all, I'm an XML newbie so go easy on me :o)
> I am writing a DTD and XSLT file for a table of astronomical 
> data, and 
> would like values to be given in SI units. For many things this means 
> astronomically large numbers like 5.0 x 10^30. I would like 
> not to have 
> to specify that using standard decimal notation (as used by 
> format-number() and xsl:decimal-number) as it would be prone 
> to errors 
> and look awful! Is there a built-in way to parse a string 
> such as "5.0 
> x 10^30" and then perform mathematical operations on it, like 
> divide it 
> by the mass of the sun (1.99 x 10^30), so it outputs a simpler number 
> like "2.5" ?
> If there is no such built in method, how would I go about 
> writing some 
> XSL/XPath voodoo to make it happen?
> 
> The lists.xml.org server doesn't seem to be responding to 
> http requests 
> at the moment so I was unable to check the archives. Apologies for 
> this.
> 
> - Nick.
> 
> 
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• References:
  • Parsing numbers in Scientific Notation
    • From: Nicholas Shanks <contact@n...>

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