• To: xml-dev@l...
• Subject: DTD replacement
• From: "Pavel A. Sher" <pavel@a...>
• Date: Tue, 15 Apr 2003 19:16:08 +0400
• Organization: Actimind
• Reply-to: "Pavel A. Sher" <pavel@a...>

Hello,

I have a question: how to replace DTD in some XML document in the most
robust way?

Suppose that I have some xml:
<?xml version='1.0'?>
<!DOCTYPE page SYSTEM "some.dtd">
<page>
...
</page>

That xml file comes from some user who uploads it via web interface
and the user could upload bad xml containing reference to his own DTD
or even internal dtd.

The question is how to replace DTD in uploaded file in order to
validate against my own DTD? Can I achieve it using standard SAX
parser?


-- 
Best regards,
 Pavel                          mailto:pavel@a...

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