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Re: HI

• To: "SARANGI,BISWAJIT (HP-Germany,ex1)" <biswajit.sarangi@h...>
• Subject: Re: HI
• From: <martin@h...>
• Date: Wed, 20 Nov 2002 16:32:31 +0000 (GMT)
• Cc: "'xml-dev@l...'" <xml-dev@l...>
• In-reply-to: <07A9D2E3B03BD4119FD300D0B747AB29077BCCEB@m...>

Biswajit,

for XSL queries you're much better off asking at xsl list:
xsl-list@l...

for this problem you need to play around with the position() function.
remember that it gives you the position of the node in the nodeset that
it's in, not its position in the document.

if you do <xsl:apply-templates select="gross|mmmmm"/> the nodeset will
consist of all 'gross' and 'mmmmm' elements for this person1 (??), and
'position() mod 2' will give you the id's you want, +/-1.

also don't use the 'id' attribute unless you really want to generate
unique (within the document) identifiers.

hth,

/m

Martin Klang
http://www.o-xml.org - the object-oriented XML programming language




On Wed, 20 Nov 2002, SARANGI,BISWAJIT (HP-Germany,ex1) wrote:

> I am learning xml and xslt and have one problem which i could not solve
> since i week.
> i havea xml file like under.
> snippet.
> <person>
>    <person1>
>      <dad>a</dad.
>      <had>1</had>
>      <mad>wfff</mad>
>      <dom>11</dom>
>      -<gross>2</gross>
>      -<mmmmm>22</mmmmm>
>      -<gross>222</gross>
>      -<mmmmm>333</mmmmm>
>      ---------
>    </person1>
>    <person1>
>      -------
>      -------
>    </person1>
> </person>
>    The two items gross and mmmmm has a "n" number of repetition.I want
> transform it into another "xml" tree
> where the repeted stuff will have one "id" numbers as a counter like 1,2,3.I
> want it serially.
>
> any one has a solution for this.
> thanking you in advance.
> biswajit sarangi
>
>
>
>
>
> -----Original Message-----
> From: Simon St.Laurent [mailto:simonstl@s...]
> Sent: Wednesday, November 20, 2002 3:23 PM
> To: xml-dev@l...
> Subject: Re:  What are the arguments *for* XHTML 2.0?
>
>
>
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  • HI
    • From: "SARANGI,BISWAJIT (HP-Germany,ex1)" <biswajit.sarangi@h...>

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