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RE: How to declare a int variable in XSL

• To: "Thomas B. Passin" <tpassin@c...>
• Subject: RE: How to declare a int variable in XSL
• From: "Manos Batsis" <m.batsis@b...>
• Date: Fri, 7 Jun 2002 16:39:17 +0300
• Cc: <xml-dev@l...>
• Thread-index: AcIOJrxo69fM2mcdSgO07L9o4SpLSgAAHvJg
• Thread-topic: How to declare a int variable in XSL

> -----Original Message-----
> From: Thomas B. Passin [mailto:tpassin@c...] 
> Sent: Friday, June 07, 2002 4:23 PM
> To: xml-dev@l...
> Subject: Re:  How to declare a int variable in XSL
> 
> 
> [David Carlisle]
> 
> > 
> > xsl-list is a better list than xml-dev for xsl questions.
> > 
> > > Do anyone know how to declare a int variable in XSL.
> > xsl (Xpath) does not have an integer type.
> > 
> > > i want to put some delimeter for each iteration in <xsl:for-each>
> > > except the first iteration.
> > <xsl:if test="position() &gt; 1"> .....
> > 
> 
> Not with xsl:for-each, though.  Position() would always be 1.

Nope, sorry. Although the position() function returns the index of the
current node *in the current node list*, the spec clearly says [1] that 

"The expression must evaluate to a node-set. The template is
instantiated with the selected node as the current node, and with a list
of all of the selected nodes as the current node list. "

[8] http://www.w3.org/TR/xslt#for-each

Regards,

Manos



> 
> Tom P
> 
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