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[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: A Query about View Construction in XML
> I have a question about view construction in xml. > > Problem Setting > =============== > Given a XML database DB, and a query Q1, either XQuery or > XSLT, we refer > to the result of Q1(DB) (the result of running query Q1 > against database > DB) as a view, say V, whose schema is Sv. In XQuery, the result of a query is not an XML document, it is a sequence of items, where each item may be either an atomic value or a node. It's meaningful to talk about the type of the result, but not about its schema. In XSLT, the result of a transformation is indeed an XML document. In general, though, the result document has no schema. > > Question > ======== > Suppose we have another query Q2 (either XQuery or XSLT) which is > formulated against schema Sv (the schema of the view V) and the > size of view V too big to fit in memory, my questions are: > > 1) Is it possible that we evaluate Q2(V), (that is running Q2 > against the > result of Q1(DB)), without materializing (or write back to > hard disk) the > result of Q1(DB)? In XSLT this is normal practice: see the JAXP interfaces, which allows a pipeline of transformations to be run as filters. However, although the intermediate result does not need to be written to disk, all existing processors require that it exists as a tree in memory. For XQuery the same notion is likely to be supported - that the result of one query can be used as input to another - but the implementations and APIs aren't yet as advanced. > > As we know, in relational database, Q2(V) can be evaluated without > materializing the view V. However, I am not sure if it is > still hold in > XML database. > Actually, SQL has another interesting property, which as that Q1 and Q2 can be combined statically into a single query and optimized as a unit. I think XQuery will also have that property, because it is a fully compositional language. You can't to the same thing with XSLT, because template rules aren't fully compositional expressions in the same way. Michael Kay Software AG home: Michael.H.Kay@n... work: Michael.Kay@s...
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