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Re: node identity in XQuery

• To: Jonathan Robie <jonathan.robie@s...>
• Subject: Re: node identity in XQuery
• From: Michael Dyck <michaeldyck@s...>
• Date: Sat, 23 Mar 2002 09:44:59 -0800
• Cc: takeha-e <takeha-e@i...>, xml-dev@l...
• Organization: intermittent
• References: <5.1.0.14.0.20020323074552.07ad9ae0@157.189.161.214>

Jonathan Robie wrote:
> 
> It is implemented in Software AG's QuiP. Here's a query that uses it:
> 
> let $a := <foo/>
> let $b := <foo/>
> return
>    <out>
>      <one>$a == $a</one>
>      <two>$a == $b</two>
>    </out>
> 
> Here are the results:
> 
>    <out>
>      <one>$a == $a</one>
>      <two>$a == $b</two>
>    </out>

I don't think that query uses the node identity operator: each of those "=="
is just two adjacent equal signs in the ElementContent of an
ElementConstructor. Instead, try:

    let $a := <foo/>
    let $b := <foo/>
    return
        <out>
            <one>{ $a == $a }</one>
            <two>{ $a == $b }</two>
        </out>

(The only difference is the insertion of braces.) For this, I think the
result should be:

    <out>
        <one>true</one>
        <two>false</two>
    </out>

-Michael Dyck

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