• To: "Banerjee, Saurabh" <sabanerjee@a...>
• Subject: Re: converting XML Schema to DTD
• From: John Cowan <jcowan@r...>
• Date: Mon, 28 Jan 2002 14:50:08 -0500
• Cc: "'xml-dev@l...'" <xml-dev@l...>
• References: <93CB722CF8BBD411AE140008C791E71603E3CAE7@p...>
• User-agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:0.9.6) Gecko/20011120

Banerjee, Saurabh wrote:

> this is not correct because the XML below is INVALID with the DTD but valid
> with the SCHEMA.
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <!--Sample XML file generated by XML Spy v4.2 U (http://www.xmlspy.com)-->
> <personnel xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
> xsi:noNamespaceSchemaLocation="D:\dtd2xs\try.xsd">
> 	<fname>String1</fname>
> 	<lname>String2</lname>
> </personnel>


That is because DTDs do not know about namespace prefixes,

or the magic properties of xsi:* to Schema.  You must declare these
attributes in your DTD by adding the following (at minimum):

<!ATTLIST personnel
	xmlns:xsi CDATA #IMPLIED
	xsi:noNamespaceSchemaLocation CDATA #IMPLIED>

-- 
John Cowan <jcowan@r...>     http://www.reutershealth.com
I amar prestar aen, han mathon ne nen,    http://www.ccil.org/~cowan
han mathon ne chae, a han noston ne 'wilith.  --Galadriel, _LOTR:FOTR_

• References:
  • converting XML Schema to DTD
    • From: "Banerjee, Saurabh" <sabanerjee@a...>

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