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Re: quick XPath question: finding /a/b/c with a default namespace

• From: "Thomas B. Passin" <tpassin@h...>
• To: xml-dev@l...
• Date: Fri, 27 Jul 2001 09:06:06 -0400

[David Carlisle]

> If you really don't want to declare a namespace then
>
> /*[local-name(.)='a']/*[local-name(.)='b']/*[local-name(.)='c']
> will get you there.
>
Unless you were unlucky enough to have another namespace defined (with its
own prefix) that also had an "a", "b", or "c" element.

Cheers,

Tom P

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  • quick XPath question: finding /a/b/c with a default namespace
    • From: James Strachan <james_strachan@y...>
  • Re: quick XPath question: finding /a/b/c with a default namespace
    • From: David Carlisle <davidc@n...>
  • Re: quick XPath question: finding /a/b/c with a default namespace
    • From: James Strachan <james_strachan@y...>
  • Re: quick XPath question: finding /a/b/c with a default namespace
    • From: David Carlisle <davidc@n...>

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