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Jonathan Borden wrote: > In particular statement [3] which defines Schema Equality as Instances(a) = Instances(b), that is two schemata are 'equal' if their instance sets are equal. ... snip ... > I have not addressed the issue of how one might actually determine that two schemata are functionally equal, but this is the general direction. Hmmm... what about 1. types(a) = types(b) 2. PSVI(a) = PSVI(b) 3. validation errors(a) = validation errors(b) 4. Reverse engineer a and b into a conceptual model: CM(a) = CM(b)
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