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Re: DTD and Illegal Construct

• From: Dan Vint <dvint@s...>
• To: Jim.Shain@a... (Jim Shain)
• Date: Wed, 10 Jan 2001 15:26:46 -0800 (PST)

Its the fact you have 2 different models (A, B, D?) and the other (A?, B, C? ...)

that says if i have an A which one of these two models am I using? It could be
either one - it doesn't have anything to do with the other elements in the models. B has the same problem and so does D.

..dan

> 
> Honestly, I'm not playing stump the experts, but what about the instance?
> 
> ((A, B, D?) | (A?, B, C?, D?, E))
> 
> In this instance 'C' can only be present if 'E' is present.
> 
> -Jim
> 
> -----Original Message-----
> (Excerpt)
> <!ELEMENT Request ((A, B, C?) | (A?, B, C?, D))> becomes
> 
> <!ELEMENT Request ((A, B, C?, D?) | (B, C?, D))>
> 

• References:
  • RE: DTD and Illegal Construct
    • From: Jim Shain <Jim.Shain@a...>

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