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Problem with sorting data within an xml using XSL

• From: desimonp@i...
• To: xml-dev@x...
• Date: Sun, 01 Oct 2000 18:30:27 -0400 (EDT)

> Say I have the following: 
> <xml id="OriginalXML"> 
> <root> 
>     <Sub_Root_Node> 
>         <Row field1="value1" field2="value2" /> 
>         <Row field1="value1" field2="value2" /> 
>         <Row field1="value1" field2="value2" /> 
>         <Row field1="value1" field2="value2" /> 
>         <Row field1="value1" field2="value2" /> 
>         <Row field1="value1" field2="value2" /> 
>     </Sub_Root_Node> 
> </root> 
> </xml> 
> <xml id="xslfile" src="filexsl.xsl"></xml> 
> 
> I want to rebuild the XML, but have it sorted based field1, if it wasn't 
> sorted at all or it was sorted on field2.  What am I missing?  I am using: 
> var newXML = OriginalXML.transferNode("xslfile.XMLDocument"); 
> 
> newXML is blank and newXML.xml is undefined... 
> 
> I tried the following:  fileXSL.xsl 
> 
> <?xml version="1.0"?> 
> <xsl:output method="xml"/>, 
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl"> 
>   <xsl:template match="/"> 
> <root> 
>   <Sub_Root_Node> 
>     <xsl:apply-templates select="Sub_Root_Node" /> 
>   </Sub_Root_Node> 
> </root> 
>   </xsl:template> 
>   <xsl:template match="Sub_Root_Node"> 
>       <xsl:for-each select="Row" order-by="lmfLateDateCount"> 
>   <Row 
>    field1="<xsl:value-of select="@field1" />" 
>    field2="<xsl:value-of select="@field2" />" 
>   /> 
>       </xsl:for-each> 
>   </xsl:template> 
> </xsl:stylesheet> 
> 
> Peter 
> 
> 
> 
> 
> 
> 
> 


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Email Address: desimonp@i...
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