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Re: SAX2 Namespace Support

• From: David Megginson <david@m...>
• To: xml-dev@i...
• Date: 05 Jan 2000 10:12:59 -0500

John Aldridge <john.aldridge@i...> writes:

> I'm sorry, I don't see the problem.  The QNames are equal if ns() and
> name() both match.  The prefix is irrelevant.  This is what I suggested in
> my definition of the equality operator above.
> 
>     if (qn1 == qn2) ...
> 
> just does the right thing.  If some application really wants to compare the
> prefixed name, it can always write:
> 
>     if (qn1.prefixedName () == qn2.prefixedName ()) ...
> 
> I'm obviously missing something, since you and other knowledgable people
> don't regard this as self evidently obvious -- can you explain the problem
> to me, please?

In principle (the principle of least surprise), it's very bad
behaviour for two objects to be == in C++ or equals() in Java if any
of their publicly-accessible fields differ.  Think of sets, for
example.


All the best,


David

-- 
David Megginson                 david@m...
           http://www.megginson.com/

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• Follow-Ups:
  • Re: SAX2 Namespace Support
    • From: Toby Speight <Toby.Speight@s...>
  • Re: SAX2 Namespace Support
    • From: David Brownell <david-b@p...>
  • Re: SAX2 Namespace Support
    • From: james anderson <James.Anderson@m...>
  • Re: SAX2 Namespace Support
    • From: John Aldridge <john.aldridge@i...>
  • RE: SAX2 Namespace Support
    • From: Leigh Dodds <ldodds@i...>

• References:
  • Re: SAX2 Namespace Support
    • From: John Aldridge <john.aldridge@i...>
  • Re: SAX2 Namespace Support
    • From: John Aldridge <john.aldridge@i...>

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