Re: SAX2 Namespace Support
John Aldridge <john.aldridge@i...> writes: > I'm sorry, I don't see the problem. The QNames are equal if ns() and > name() both match. The prefix is irrelevant. This is what I suggested in > my definition of the equality operator above. > > if (qn1 == qn2) ... > > just does the right thing. If some application really wants to compare the > prefixed name, it can always write: > > if (qn1.prefixedName () == qn2.prefixedName ()) ... > > I'm obviously missing something, since you and other knowledgable people > don't regard this as self evidently obvious -- can you explain the problem > to me, please? In principle (the principle of least surprise), it's very bad behaviour for two objects to be == in C++ or equals() in Java if any of their publicly-accessible fields differ. Think of sets, for example. All the best, David -- David Megginson david@m... http://www.megginson.com/ xml-dev: A list for W3C XML Developers. To post, mailto:xml-dev@i... Archived as: http://www.lists.ic.ac.uk/hypermail/xml-dev/ and on CD-ROM/ISBN 981-02-3594-1 To unsubscribe, mailto:majordomo@i... the following message; unsubscribe xml-dev To subscribe to the digests, mailto:majordomo@i... the following message; subscribe xml-dev-digest List coordinator, Henry Rzepa (mailto:rzepa@i...)
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