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[XML-DEV Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] how the parser locate dtd files
hi,
I am new to xml and need to do a quick prototype of how to retrieve
information from other web site using xml format. I got a parsing error of
** Parsing error, line 2, uri null
Relative URI "my.dtd"; cannot be resolved without a document URI.
I am using Sun's xml parser, and the code looks like
URL source = new URL(url);
URLConnection conn = source.openConnection();
conn.setDoInput(true);
InputStream is = conn.getInputStream();
input = Resolver.createInputSource("text/xml;charset=UTF-8", is,
false, "http");
parser = ParserFactory.makeParser();
parser.setDocumentHandler(this);
parser.setErrorHandler(this);
parser.parse(input);
The document that I am retrieving from the url looks like
<?xml version="1.0" encoding="iso-8859-1"?>
<!DOCTYPE mydoc SYSTEM "my.dtd">
.....
The my.dtd is at the same location as the document, but obviously the parser
doesn't know how to resolve it. What I need to do for configuring the
parser? I am kind of lost by reading the document, any help will be greatly
appreciated.
Thanks.
Weihong.
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