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shivan mahajan

Subject: Search and replace hexadecimal value
Author: shivan mahajan
Date: 17 Oct 2005 03:13 PM

Hi,
I want to replace an hexadecimal value in the xml file by using xslt. The hexadecimal value looks like this:
it is a space.
This is the code i am using:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/02/xpath-functions" xmlns:xdt="http://www.w3.org/2005/02/xpath-datatypes">
<xsl:template match="/">
<Budget_History_struct>
<xsl:for-each select="leb_connect/Budget">
<Budget_history>
<xsl:variable name="clientBudgetID" select="@clientBudgetID"/>
<xsl:variable name="mtrNumber" select="Matter/@mtrNumber"/>
<xsl:variable name="editTimestamp" select="EditHistoryList/EditHistory/@editTimestamp"/>
<xsl:variable name="editDescription" select="EditHistoryList/EditHistory/@editDescription"/>
<xsl:for-each select="EditHistoryList/EditHistory/User">
<xsl:element name="User">
<xsl:variable name="employeeID" select="@employeeID"/>
<xsl:variable name="firstName" select="@firstName"/>
<xsl:variable name="middleName" select="@middleName"/>
<xsl:variable name="lastName" select="@lastName"/>
<xsl:variable name="userName" select="@userName"/>
<xsl:variable name="activeDate" select="@activeDate"/>
<xsl:attribute name="clientBudgetID"><xsl:value-of select="$clientBudgetID"/></xsl:attribute>
<xsl:attribute name="mtrNumber"><xsl:value-of select="$mtrNumber"/></xsl:attribute>
<xsl:attribute name="editTimestamp"><xsl:value-of select="$editTimestamp"/></xsl:attribute>
<xsl:attribute name="editDescription"><xsl:value-of select="$editDescription"/></xsl:attribute>
<xsl:attribute name="employeeID"><xsl:value-of select="$employeeID"/></xsl:attribute>
<xsl:attribute name="firstName"><xsl:value-of select="$firstName"/></xsl:attribute>
<xsl:attribute name="middleName"><xsl:value-of select="$middleName"/></xsl:attribute>
<xsl:attribute name="lastName"><xsl:value-of select="$lastName"/></xsl:attribute>
<xsl:attribute name="userName"><xsl:value-of select="$userName"/></xsl:attribute>
<xsl:attribute name="activeDate"><xsl:value-of select="$activeDate"/></xsl:attribute>
</xsl:element>
</xsl:for-each>
</Budget_history>
</xsl:for-each>
</Budget_History_struct>
</xsl:template>
</xsl:stylesheet>

Thanks
shivan

Minollo I.

Subject: Search and replace hexadecimal value
Author: Minollo I.
Date: 17 Oct 2005 03:30 PM

Shivan,
some suggestions have already been posted here: http://www.stylusstudio.com/ssdn/default.asp?action=9&read=4282&fid=48

If you have additional general XSLT questions a better place to post them is probably the xsl-list at mulberrytech.com

Thanks,
Minollo

shivan mahajan

Subject: Search and replace hexadecimal value
Author: shivan mahajan
Date: 17 Oct 2005 03:55 PM

i havent get my answer. I subscribed there also. But i dont know how to post the question. Because i couldnt find anyplace to post new message. i thought of doing through email. But i dont know which email address to use.

thanks
shivan

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