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bb said

Subject: a href in a xml to xslt transform
Author: bb said
Date: 01 Apr 2005 03:45 AM

I have an xml file that is converted to html with xslt.

What I am trying to figure out is how to include a url in the xml file and have it transformed into an html a href link

For example the xml would be

<links>
<link>http://www.yahoo.com</link>
</links>

And the resulting html after xslt transform would be

<a href=”http://www.yahoo.com>Yahoo!</a>

This would also mean having the linked text (Yahoo!) defined somewhere in the xml file

(Deleted User)

Subject: a href in a xml to xslt transform
Author: (Deleted User)
Date: 01 Apr 2005 09:50 AM

Hi Said,

>[..] For example the xml would be
>
><links>
><link>http://www.yahoo.com</link>
></links>
>

You don't specify how you reach that link, so I am assuming you just
want to convert a list of URL into an HTML with the corresponding
clickable links.
In this case, this stylesheet should do the work:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html"/>
<xsl:template match="/">
<html>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>

<xsl:template match="link">
<a href="{text()}">
<xsl:value-of select="@text"/>
</a>
</xsl:template>
</xsl:stylesheet>

Hope this helps,
Alberto

bb said

Subject: a href in a xml to xslt transform
Author: bb said
Date: 01 Apr 2005 12:08 PM

Thank you Alberto,

I'm pretty new to xml (just started using XML this week) and I was wondering if you could show me exactly how both the xml and xslt should look to make this work.

Also I'm not sure what "{text()}" refers to.

What the ultimate output is supposed to be is an HTML table with 5 <td></td> using for-each in xslt. The first 4 td's only contain text but the last one will contain several links to files. Here is the actual xml and xslt I will be using:

XML: (transform.xml)

<?xml version="1.0" encoding="iso-8859-1"?>
<?xml-stylesheet href="transform.xsl" type="text/xsl"?>

<opportunity>
<category>text</category>
<program>text</program>
<description>text</description>
<funder>text</funder>
<duedate>text</duedate>
<furtherinfo>multiple URL's defined here or somewhere in the XML</furtherinfo>
</opportunity>

XSLT: (transform.xsl)

<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>Funding Opportunities</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th>Program</th>
<th>Description</th>
<th>Funder</th>
<th>Due Date</th>
<th>Further Info</th>
</tr>
<xsl:for-each select="allopportunities/opportunity">
<tr>
<td><xsl:value-of select="program"/></td>
<td><xsl:value-of select="description"/></td>
<td><xsl:value-of select="funder"/></td>
<td><xsl:value-of select="duedate"/></td>
<td><xsl:value-of select="furtherinfo"/>links to files go here</td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>

This example transforms just fine but I still can't figure out how to get the links in there.

Thanks for your help.

bb said

Subject: a href in a xml to xslt transform
Author: bb said
Date: 01 Apr 2005 12:11 PM

in my example I closed </xsl:for-each> twice, that's a typo.

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