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Xpath of each element
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Subject:
Xpath of each element
Author:
sol dgn
Date:
01 Jul 2011 08:37 AM
Hello All.
I want to extract XPATH of all xml elemememts in any xml file.
Is there any way to get it?
I know name() function but it just give me current node value. I need xpath of element.
Thanks.
next
Subject:
Xpath of each element
Author:
Ivan Pedruzzi
Date:
20 Jul 2011 03:59 PM
This sounds like a navigation exercise
<xsl:stylesheet version="1.0" xmlns:xsl="
http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:template match="*">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="concat('/', local-name(.))"/>
</xsl:for-each>
<xsl:value-of select="'
'"/>
<xsl:for-each select="@*">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="concat('/', local-name(.))"/>
</xsl:for-each>
<xsl:value-of select="concat('/@', local-name(.))"/>
<xsl:value-of select="'
'"/>
</xsl:for-each>
<xsl:apply-templates select="*"/>
</xsl:template>
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
</xsl:stylesheet>
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Subject:
Xpath of each element
Author:
sol dgn
Date:
11 Aug 2011 07:23 AM
Thanks.
I had also received few other reply. I am pasting link to another thread.
http://www.ibm.com/developerworks/forums/thread.jspa?threadID=364457&tstart=0
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