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Kevin NovickSubject: Copy XML Based on IF Conditions
Author: Kevin Novick
Date: 20 Jan 2011 02:41 PM
Originally Posted: 20 Jan 2011 02:40 PM
I want to copy the <trade> elements that match when

SECURITY_TYPE = 1 and SECURITY_SUB_TYPE = 99
OR
SECURITY_TYPE = 1 and SECURITY_SUB_TYPE = 12

Here is a snippet of the XML

<trade>
<PORTFOLIO_NUMBER>123</PORTFOLIO_NUMBER>
<TICKER>F</TICKER>
<SECURITY_TYPE>1</SECURITY_TYPE>
<SECURITY_SUB_TYPE>99</SECURITY_SUB_TYPE>
<PRICE>17.98</PRICE>
<QUANTITY>1</QUANTITY>
</trade>
<trade>
<PORTFOLIO_NUMBER>123</PORTFOLIO_NUMBER>
<TICKER>C</TICKER>
<SECURITY_TYPE>1</SECURITY_TYPE>
<SECURITY_SUB_TYPE>12</SECURITY_SUB_TYPE>
<PRICE>3.42</PRICE>
<QUANTITY>1</QUANTITY>
</trade>
<trade>
<PORTFOLIO_NUMBER>123</PORTFOLIO_NUMBER>
<TICKER>AAPL</TICKER>
<SECURITY_TYPE>2</SECURITY_TYPE>
<SECURITY_SUB_TYPE>4</SECURITY_SUB_TYPE>
<PRICE>300.34</PRICE>
<QUANTITY>1</QUANTITY>
</trade>

Here is my failed XSLT

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
<xsl:output method="xml" indent="yes"/>

<xsl:template match="@* | node()">
<xsl:copy>
<xsl:if test="(SECURITY_TYPE = 1 and SECURITY_SUB_TYPE = 99) or
(SECURITY_TYPE = 1 and SECURITY_SUB_TYPE = 12)">

<xsl:value-of select="."/>

</xsl:if>
</xsl:copy>
</xsl:template>

</xsl:stylesheet>
   
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