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Fred FooSubject: Count unique values using XSLT
Author: Fred Foo
Date: 07 Jul 2010 07:45 AM
Originally Posted: 07 Jul 2010 07:43 AM
Hi,

I have (what should be) a simple XSLT problem. How can I count nodes with a unique value, and sort into some sequence?

Here's my simple example:

<root>
<cust>
<lastname>smith</lastname>
<firstname>bob</firstname>
</cust>
<cust>
<lastname>smith</lastname>
<firstname>joe</firstname>
</cust>
<cust>
<lastname>brown</lastname>
<firstname>joe</firstname>
</cust>
<cust>
<lastname>smith</lastname>
<firstname>pete</firstname>
</cust>
</root>

Here's what I'm hoping to see:

brown 1
smith 3

In other words, I want to see how many customers have each lastname, sorted alphabetically ascending.

Thanks
Postnext
Ivan PedruzziSubject: Count unique values using XSLT
Author: Ivan Pedruzzi
Date: 08 Jul 2010 11:17 AM

Tipical grouping problem



Ivan Pedruzzi
Stylus Studio Team


Documentkeys_XSLT_1.xsl


Documentkeys_XSLT_2.xsl
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Fred FooSubject: Count unique values using XSLT
Author: Fred Foo
Date: 11 Jul 2010 11:50 PM
Many thanks. For others reference, this is the code I ended up going with:

<xsl:key name="custs-by-lastname" match="cust" use="lastname"/>
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="/root/cust[count(. | key('custs-by-lastname', lastname)[1]) = 1]">
<xsl:sort select="lastname"/>
<table border="1">
<tr>
<td>
<xsl:value-of select="lastname"/>
</td>
<td>
<xsl:value-of select="count(key('custs-by-lastname', lastname))"/>
</td>
</tr>
</table>
</xsl:for-each>
</body>
</html>
</xsl:template>
   
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