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zakir techSubject: xslt elements help
Author: zakir tech
Date: 21 Jun 2009 10:09 PM
Hello,

I have XML , I am trying to create a xslt on these xml.



<Qxml>
<Qxml>
<Net>
<Property Name="DOCTOR" SName="DOC" LongDesc="YYY DOC" Code="666" STC="1"/>
<Property Name="ENGINEER" SName="ENG" LongDesc="XXX ENG" Code="777" STC="2"/>
<Property Name="TEACHER" SName="TEA" LongDesc="ZZZ TEA" Code="888" STC="3"/>
<Property Name="CLERK" SName="CLE" LongDesc="TTT CLE" Code="999" STC="4"/>
</Net>
</Qxml>
</Qxml>


I want the output xml in below format.


<Net>
<SName>DOC</SName><Code>666</Code>
<SName>ENG</SName><Code>777</Code>
<SName>TEA</SName><Code>888</Code>
<SName>CLE</SName><Code>999</Code>
</Net>



I am only getting 1 row , that is first rows.

<xsl:element name="Name">
<xsl:value-of select="//@SName"/>
<xsl:element name="Code"">
<xsl:value-of select="//@Code"/>
</xsl:element>
</xsl:element>


output I am getting which is incorrect

<Name>DOC<Code>666</Code>
</Name>

Please help

Thanks
Posttop
James DurningSubject: xslt elements help
Author: James Durning
Date: 22 Jun 2009 10:29 AM
You probably want to use a for-each here. eg:

<xsl:template match="Net">
<xsl:copy>
<xsl:for-each select="Property">
<SName><xsl:value-of select="@SName"/></SName>
<Code><xsl:value-of select="@Code"/></Code>
</xsl:for-each>
</xsl:copy>
</xsl:template>
   
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