Subject:wild card chracter usage in XSL Author:Tony Lavinio Date:28 Apr 2009 08:06 AM
First, this is the XQuery forum, not the XSLT forum.
Second, neither '=' nor 'contains' does wildcards.
You need an XSLT 2 or XQuery processor to do this.
The XPath syntax can be right in the specification.
I found it by Google-ing for "xpath 2.0", opening the
W3C spec, and looking for the word "regular".