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T SSubject: Transform multiple node values to one node value
Author: T S
Date: 16 Dec 2008 11:09 AM
I need to transform the following XML

<root>
<person>
<name>Name-ABC</name>
<complete-address>
<address-line type="Apt#">10</address-line>
<address-line type="street">Wall St</address-line>
<address-line type="city">New York</address-line>
<address-line type="state">NY</address-line>
<address-line type="Zip">10005</address-line>
</complete-address>
</person>
<person>
.
.
</person>
</root>

to

<root>
<person>
<name>Name-ABC</name>
<complete-address>
<address-line type="Apt#">10</address-line>
<address-line type="street">Wall St</address-line>
<complete-address>
<address>City=New York;State=NY;Zip=10005</address>
</person>
</root>

Appreciate any help in providing a solution using XSL

Thanks
TS
Posttop
James DurningSubject: Transform multiple node values to one node value
Author: James Durning
Date: 16 Dec 2008 04:33 PM
<xsl:template match="complete-address">
<xsl:copy>
<xsl:copy-of select="address-line[@type='Apt#' or @type='street']"/>
</xsl:copy>
<address>
<xsl:apply-templates select="address-line[not(@type='Apt#' or @type='street')]"/>
</address>
</xsl:template>
<xsl:template match="address-line">
<xsl:value-of select="@type">
<xsl:text>=</xsl:text>
<xsl:value-of select="."/>
<xsl:if test="not(last())">
<xsl:text>;</xsl:text>
</xsl:if>
</xsl:template>
   
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