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Mike SappSubject: XSLT Transformation
Author: Mike Sapp
Date: 20 Jan 2008 09:20 PM
Hello,

Im having trouble with a transformation. The target release date is getting multiple results. Ive tried to do the following however I only need one result in the Release Attribute of the result xml file:

XSLT conversion:

<xsl:template match="/">
<xsl:for-each select="a:ReleaseUploadDocument/a:Releases/a:Release">
<document>
<Release>
<xsl:attribute name="releaseDate">
<xsl:value-of select="a:Tracks/a:Track/a:NonExclusiveRelDate[1]"/>
</xsl:attribute>
</Release
</document>


Target is:
<document>
<release releaseDate="XX">
<track-list>
<track></track>
</track-list>
</release>
</document>

Source is:
<ReleaseUploadDocument>
<Releases>
<Release>
<Tracks>
<Track>
<NonExclusiveRelDate>2008-12-1</NonExclusiveRelDate>
</Track>
<Track>
<NonExclusiveRelDate>2008-12-1</NonExclusiveRelDate>
</Track>
</Tracks>
</Release>
<Release>
<Tracks>
<Track>
<NonExclusiveRelDate>2008-2-1</NonExclusiveRelDate>
</Track>
<Track>
<NonExclusiveRelDate>2008-2-1</NonExclusiveRelDate>
</Track>
</Tracks>
</Release>
</Releases>
</ReleaseUploadDocument>


Any help would be greatly appreciated
Postnext
James DurningSubject: XSLT Transformation
Author: James Durning
Date: 21 Jan 2008 12:09 PM
Not exactly sure, but perhaps parentheses are needed:

<xsl:value-of select="(a:Tracks/a:Track/a:NonExclusiveRelDate)[1]"/>
Postnext
Mike SappSubject: XSLT Transformation
Author: Mike Sapp
Date: 21 Jan 2008 06:47 PM
That did the trick! Thank you-!

Just to confirm, parenthesis would mean that output would only be one value? (im still learning-)
Posttop
James DurningSubject: XSLT Transformation
Author: James Durning
Date: 22 Jan 2008 10:28 AM
Parentheses groups all the nodes together so that the [1] takes the first of these nodes.

Otherwise the [1] applies to each node as it is being queried, and since each NonExclusiveRelDate is the first node in the Track node, you get all of them.
   
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