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peleg kSubject: getting an xml from an inner node
Author: peleg k
Date: 15 May 2007 04:47 PM
Originally Posted: 15 May 2007 04:48 PM
i have xml like this :
<root>
<sub1>
....
</sub1>
<data>
<xml1>
<x1>aaa</x1>
<x2>bbb</x2>
</xml1>
</data>
</root>
and i am trying to get from the above xml the "xml1" xml.
i do this by :

[CODE]
<xsl:template match="xml1">
<xsl:variable name="Value2">
<xsl:value-of select="."/>
</xsl:variable>
<xsl:value-of disable-output-escaping="yes" select="translate ( $Value2, ' &#xD;&#xA;', '')"/>
</xsl:template>
[/CODE]

but instead of getting the xml1 in 1 line i recive only the nodes value like :
aaabbb

later on i got some help and got XSL file that suppose to do the work.
the proble is that i recive from on one xml an xml but on the other i recive :
Access is denied. Error processing resource 'file:///C:/temp/peleg.xsl'.

any idea why?
(i have attched the 2xml+xsl)
i checked and thee is no diffrence maybe some else will know why?

thnks in advance
peleg


Unknowntemp.zip
2 xml+1xsl
Posttop
Elias HuterSubject: getting an xml from an inner node
Author: Elias Huter
Date: 16 May 2007 03:11 AM
If you want the value + the tags you have to you use xsl:copy instead of xsl:value-of.

Heres a template of how to do it:

<xsl:template match="/">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates mode="copy"/>
</xsl:copy>
</xsl:template>

<xsl:template match="@*|node()" mode="copy">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates mode="copy"/>
</xsl:copy>
</xsl:template>

For me both XML files work, maybe you should try to move your files to a different path, best simply to C:\ to be sure that's not where the error comes from?
   
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