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How to exit xsl:for each if condition is satisfied in XSL
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Subject:
How to exit xsl:for each if condition is satisfied in XSL
Author:
Priya Anbulakshmi
Date:
13 Apr 2007 08:19 AM
Hi,
I have one situation which i need to exit from the for loop . How can i do that in xsl?
XML:
<root>
<a>
<b>1</b>
<c>1</c>
</a>
<a>
<b>0</b>
<c>0</c>
</a>
<a>
<b>1</b>
<c>1</c>
</a>
</root>
XSL Snippet:
<xsl:for-each select="root/a">
<xsl:if test="b = 1 and c = 1 ">
X
</xsl:if>
</xsl:for-each>
I want output of "X" alone but i m getting "XX". How to stop the for loop once i got my condition satisfied?
next
Subject:
How to exit xsl:for each if condition is satisfied in XSL
Author:
(Deleted User)
Date:
13 Apr 2007 08:32 AM
Hi Priya,
XSLT is not a procedural language... you have to work on node sets, like this:
<xsl:for-each select="root/a[b = 1 and c = 1][1]">
X
</xsl:for-each>
Alberto
next
Subject:
How to exit xsl:for each if condition is satisfied in XSL
Author:
Priya Anbulakshmi
Date:
13 Apr 2007 10:05 AM
Thanks Alberto.
It worked. Then how will you do else condition say if the condition is not matching i need print "Y"
top
Subject:
How to exit xsl:for each if condition is satisfied in XSL
Author:
(Deleted User)
Date:
13 Apr 2007 10:14 AM
Priya,
in this case you don't want to iterate at all; you need either a xsl:if or a xsl:choose on the same XPath expression.
Alberto
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