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Priya Anbulakshmi

Subject: How to exit xsl:for each if condition is satisfied in XSL
Author: Priya Anbulakshmi
Date: 13 Apr 2007 08:19 AM

Hi,

I have one situation which i need to exit from the for loop . How can i do that in xsl?

XML:

<root>
<a>
<b>1</b>
<c>1</c>
</a>

<a>
<b>0</b>
<c>0</c>
</a>

<a>
<b>1</b>
<c>1</c>
</a>
</root>

XSL Snippet:

<xsl:for-each select="root/a">
<xsl:if test="b = 1 and c = 1 ">
X
</xsl:if>
</xsl:for-each>

I want output of "X" alone but i m getting "XX". How to stop the for loop once i got my condition satisfied?

(Deleted User)

Subject: How to exit xsl:for each if condition is satisfied in XSL
Author: (Deleted User)
Date: 13 Apr 2007 08:32 AM

Hi Priya,
XSLT is not a procedural language... you have to work on node sets, like this:

<xsl:for-each select="root/a[b = 1 and c = 1][1]">
X
</xsl:for-each>

Alberto

Priya Anbulakshmi

Subject: How to exit xsl:for each if condition is satisfied in XSL
Author: Priya Anbulakshmi
Date: 13 Apr 2007 10:05 AM

Thanks Alberto.

It worked. Then how will you do else condition say if the condition is not matching i need print "Y"

(Deleted User)

Subject: How to exit xsl:for each if condition is satisfied in XSL
Author: (Deleted User)
Date: 13 Apr 2007 10:14 AM

Priya,
in this case you don't want to iterate at all; you need either a xsl:if or a xsl:choose on the same XPath expression.

Alberto

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