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Rahul Puttagunta

Subject: xml, xslt question
Author: Rahul Puttagunta
Date: 03 Oct 2006 07:29 PM
Originally Posted: 03 Oct 2006 07:26 PM

Would you please help me create an xsl stylesheet?

I need to transform this xml using an xslt stylesheet. I basically need to trim spaces from the attributes and then save it into another xml file.
Since the post is trimming it for me, I am replacing the spaces with
X's.

Source:

<searchresults>

<v w="21XXXXXXXXXXXXXXXXX">
<f n="BrandCode" v="1XXXXXXXXXXXXXXX"/>
<f n="state" v="AKXXXXXXXXXXXXXXXXXX"/>
<f n="city" v="AnchorageXXXXXXXXXXX"/>
<f n="name" v="name1"/>

</v>
<v w="21">
<f n="BrandCode" v="7"/>
<f n="state" v="AKXXXXXXXXXXXXXXXXX"/>
<f n="city" v="FairbanksXXXXXXXXXXXXXXXXXXX"/>
<f n="name" v="name2"/>

</v>
</searchresults>

Result:

<searchresults>

<v w="21">
<f n="BrandCode" v="1"/>
<f n="state" v="AK"/>
<f n="city" v="Anchorage"/>
<f n="name" v="name1"/>

</v>
<v w="21">
<f n="BrandCode" v="7"/>
<f n="state" v="AK"/>
<f n="city" v="Fairbanks"/>
<f n="name" v="name2"/>

</v>
</searchresults>

Your help is greatly appreciated.

Rahul Puttagunta

Subject: xml, xslt question
Author: Rahul Puttagunta
Date: 04 Oct 2006 12:54 PM

bump ....

I guess i just need the XSL transformation that THIS particular forum is doing for trimming the attribute spaces on my XML.

Thank you,
Rahul.

James Durning

Subject: xml, xslt question
Author: James Durning
Date: 05 Oct 2006 05:52 PM
Originally Posted: 05 Oct 2006 05:51 PM

<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates select="node()"/>
</xsl:copy>
</xsl:template>

<xsl:template match="@*">
<xsl:attribute name="{name()}">
<xsl:value-of select="translate(.,' ','')
</xsl:attribute>
</xsl:template>

you could also use normalize-space()

Rahul Puttagunta

Subject: xml, xslt question
Author: Rahul Puttagunta
Date: 06 Oct 2006 04:10 PM

Thank you, but the XSL you gave me look like they are two different XSL's . Also, one of the two xml's was not well formed. Can you help me out please?

Thank you,
Rahul.

Rahul Puttagunta

Subject: xml, xslt question
Author: Rahul Puttagunta
Date: 09 Oct 2006 10:57 AM

My friend posted this in a google groups forum, and, somebody answered. Here is the solution:

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:template match="/">
<xsl:apply-templates select="searchresults" mode="normalize"/>
</xsl:template>
<xsl:template match="node()" mode="normalize">
<xsl:copy >
<xsl:apply-templates select="@*" mode="normalize"/>
<xsl:apply-templates select="*" mode="normalize"/>
</xsl:copy>
</xsl:template>
<xsl:template match="@*" mode="normalize">
<xsl:attribute name="{name(.)}">
<xsl:value-of select="normalize-space(.)"/>
</xsl:attribute>
</xsl:template>

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