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Markus schmidt

Subject: Hard Problem in XSLT
Author: Markus schmidt
Date: 08 Jun 2006 05:33 AM

hello all,

i have got a big problem, which I haven't resolved yet.

I have to transform from one xml file to another, but it seems that xsl(t) is not able to resolve my transformations.
i have got following xml-source (explanatory):

<table name="table1" schema="schema1"/>
<table name="table2" schema="schema2"/>
<table name="table3" schema="schema1"/>
<table name="table4" schema="schema1"/>

the output should be:

<Schema name="schema1" tables="table1 table3 table4"/>
<Schema name="schema2" tables="table2"/>

How to transform this kind of structure
1. without depending of any xslt-processor
2. and do the step in one transformation!
(not two xsl transformation files)

cheers for any response.
I am desparate with that problem..

Minollo I.

Subject: Hard Problem in XSLT
Author: Minollo I.
Date: 08 Jun 2006 10:13 AM

It's the usual XSLT grouping problem; you may want to search the forum for more help:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:key name="tables" match="//table" use="@schema"/>

<xsl:template match="/">
<root>
<xsl:for-each select="//table[generate-id() = generate-id(key('tables', @schema)[1])]">
<xsl:variable name="tableName" select="@schema"/>
<schema name="{$tableName}">
<xsl:attribute name="tables">
<xsl:for-each select="//table[@schema = $tableName]">
<xsl:value-of select="@name"/><xsl:text> </xsl:text>
</xsl:for-each>
</xsl:attribute>
</schema>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>

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