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Sam SamSubject: Summation in XSLT
Author: Sam Sam
Date: 28 Feb 2006 03:04 AM
Originally Posted: 27 Feb 2006 11:56 PM
Hi Please do let me know as to how do we handle the following scenario, Source XML <?xml version="1.0" encoding="UTF-8" ?> <root>< <del> <value> <p1>10</p1> <p2>5</p2> </value> <value> <p1>10</p1> <p2>5</p2> </value> <value> <p1>10</p1> <p2>15</p2> </value> </del> </root> Target XML <?xml version="1.0" encoding="UTF-8" ?> <root> <del> <value>35</value> </del> </root> So basically what i am trying to achieve is, i will have to compare the value <p1> and <p2> and pick up the greater of the 2 and sum it up. So in our above example it becomes 10 + 10 + 15 = 35 How can this be achieved using XSLT 1.0. regards Sam

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Minollo I.Subject: Summation in XSLT
Author: Minollo I.
Date: 28 Feb 2006 10:07 AM
There are ways to do this in a much simpler way using XSLT 2.0; and probably also using XSLT 1.0; but this should do something similar to what you are looking for:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<root>
<del>
<value>
<xsl:apply-templates select="/root/del/value[1]"/>
</value>
</del>
</root>
</xsl:template>
<xsl:template match="value">
<xsl:param name="curSum" select="0"/>
<xsl:variable name="aValue">
<xsl:choose>
<xsl:when test="p1 &gt; p2">
<xsl:value-of select="p1"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="p2"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:choose>
<xsl:when test="following-sibling::value[1]">
<xsl:apply-templates select="following-sibling::value[1]">
<xsl:with-param name="curSum" select="$curSum+$aValue"/>
</xsl:apply-templates>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$curSum+$aValue"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
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Sam SamSubject: Summation in XSLT
Author: Sam Sam
Date: 28 Feb 2006 10:36 AM
Thanks a lot Minolo.

cheers
Sam
   
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