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Topic

farshad farzan

Subject: full xpath to a node
Author: farshad farzan
Date: 17 Jan 2006 09:30 PM

I have an IXMLDOMNode variable called foo ,
that gets pointed by the user in the document.
I want to have a way to find the full xpath to this node.

for example,

<a> <b> <c> test </c> </b> </a>

let's say foo.nodeName shows >>> c

how can I get the full xpath to c i.e /a/b/c

Tony Lavinio

Subject: full xpath to a node
Author: Tony Lavinio
Date: 18 Jan 2006 09:07 AM

This isn't really a Stylus Studio question, but if you go to
http://windowssdk.msdn.microsoft.com/library/default.asp?url=/library/en-us/xmlsdk/html/89337bfc-c5a7-44bc-9e98-cbf2363ac42c.asp
you can see that you can fetch the name of the current node with
the 'nodeName' method, and then iterate, each time walking up the
tree one level with the 'parentNode' method. By concatenating
together the names with '/' in between, you can build your path.

farshad farzan

Subject: full xpath to a node
Author: farshad farzan
Date: 18 Jan 2006 08:39 PM

thanks for your response, I found a code writen in pyton, and I converted it to csharp , however,
it works for an element but not for attribute.. node.OwnerElement gives me error. !

public string findfullpath( IXMLDOMNode node)
{
IXMLDOMNode previous, ancestor;
string step ;
int count;
ancestor = null;
step = "";

if (node.nodeType == (DOMNodeType) 1 ) //NODE_ELEMENT
{
count = 1;
previous = node.previousSibling;
while ( previous != null)
{
if ( previous.baseName == node.baseName ) count += 1;
previous = previous.previousSibling;
// step = node.nodeName+"["+ count+"]";
step = node.nodeName;
ancestor = node.parentNode;
}
}

else if ( node.nodeType == (DOMNodeType) 2) // NODE_ATTRIBUTE
{
step = node.nodeName;

ancestor = node.OwnerElement ;
count = 1;
previous = node.previousSibling;
while ( previous != null)
{
if ( previous.nodeType == node.nodeType) count += 1;
previous = previous.previousSibling;
ancestor = node.parentNode;
}
ancestor = node;
}
if ( ancestor.parentNode != null)
return findfullpath(ancestor) + "/" + step;
else
return "/" + step;

}

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