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Surekha PalaparthySubject: Help in creating style sheet
Author: Surekha Palaparthy
Date: 11 Aug 2005 08:39 AM
Hi all
I am new to XSLT.New in the sense i just started going through this today bcos i have a requirement where I have to read an XML file and generate another XML file querying it.Today i came to know that it can be done by using XSLT.

Now coming to my question ..
I have an XML file .The content will be somehting like this

<?xml version="1.0" encoding="utf-16"?>
<MainHead xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><Apply>true</Apply>
<subhead1>This is the subhead</subhead1>
<subhead2><Apply>true</Apply>
<Name>XSLT01cefe</Name>
<value>001</value>
</subhead2>
<subhead2><Apply>true</Apply>
<Name>XSLT02abc</Name>
<value>003</value>
</subhead2>
<subhead2><Apply>true</Apply>
<Name>DIFF></Name>
<value>oof</value>
</subhead2>
</MainHead>

The code that i mentioned is only a sample.My job is to query a very big file.
I have to query the file which is of the format given as sample above.
My requirement is to get the values of all the nodes whose "Name" elements start with XSLT0.

Can any one help me in giving a sample to do this??
I want a query where I can go through each node and select the one which satisifies the condition of XSLT0.

Pleas help me as early as possible as my next task cannot be started before this is done
Thanks in advance
Posttop
Ivan PedruzziSubject: Help in creating style sheet
Author: Ivan Pedruzzi
Date: 11 Aug 2005 09:42 AM

This one of the possible solutions

Hope this helps
Ivan Pedruzzi
Stylus Studio Team

<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
<root>
<xsl:for-each select="//Name[starts-with(., 'XSLT0')]">
<xsl:copy-of select="../value"/>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>

   
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