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Clement SSubject: Reorder Node
Author: Clement S
Date: 12 Jul 2005 04:39 PM
Is is possible to do this?
From This:
<A>
<B>
<C>111</C>
<C>222</C>
<C>333</C>
</B>
<D>aaa</D>
<D>bbb</D>
<D>ccc</D>
</A>
To this:
<A>
<B>
<C>111
<D>aaa</D>
</C>
<C>222
<D>bbb</D>
</C>
<C>333
<D>ccc</D>
</C>
</B>
</A>

Node C and D will always be 1-to-1.
Thanks in advance.
Postnext
Ivan PedruzziSubject: Reorder Node
Author: Ivan Pedruzzi
Date: 13 Jul 2005 02:32 AM
Clement,

The following simple solution uses the position() function to bind each C with a D at the same position in document order.

Hope this helps
Ivan Pedruzzi
Stylus Studio Team


<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>

<xsl:template match="B">
<xsl:copy>
<xsl:apply-templates select="C"/>
</xsl:copy>
</xsl:template>

<xsl:template match="C">
<xsl:variable name="position" select="position()"/>
<xsl:copy>
<xsl:apply-templates/>
<xsl:copy-of select="//A/D[position() = $position]"/>
</xsl:copy>
</xsl:template>

<xsl:template match="D"/>

</xsl:stylesheet>

Posttop
Clement SSubject: Reorder Node
Author: Clement S
Date: 13 Jul 2005 10:30 AM
Thanks, it work.
   
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