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Neal  WaltersSubject: Mystery xslt wrapper around my stylesheet?
Author: Neal Walters
Date: 11 May 2005 10:26 AM


I have a stylesheet something like this:

<xsl:template match="/">
<Cart>
<CartTotal>
<xsl:value-of select="Cart/CartItem[1]/CartTotal"/>
</CartTotal>
<Param name="time_entered"><xsl:value-of select="fn:current-dateTime()"/></Param>

</Cart>
</xsl:template>


I have a two pronged question:
1) How to set the value of time_entered to current date and time.
I'm getting an error that namespace fn is not edefined.
2) I went to another stylehsheet that I had, and it had the following xml at the top.

<?xml version='1.0' ?>
<xsl:stylesheet version="1.0" exclude-result-prefixes="msxsl var" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:var="http://schemas.microsoft.com/BizTalk/2003/var" xmlns:ns0="http://www.odimo.com/OrderEntry/OdimoGenericOrder.xsd">
<xsl:output omit-xml-declaration="yes" version="1.0" method="xml" indent="yes"/>
(and the corresponding close tag at the bottom).

I tried adding the <xsl:stylesheet> tag to my Cart stylesheet above, and started getting strange errors. When I add <?xml version='1.0' ?>
to the top of the Cart Stylesheet, it says error online 3. So somehow, it thinks the <?xml> directive is on line 3.

Do I somehow have a hidden <xsl:stylesheet> on line 1 and 2 that I cannot see?

Neal




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Ivan PedruzziSubject: Mystery xslt wrapper around my stylesheet?
Author: Ivan Pedruzzi
Date: 11 May 2005 05:32 PM
Hi Neal,

You need to close the stylesheet element.
Below is a well formed version of what you have described.
Note that this is XSLT 2 stylesheet so it runs only with the Saxon processor.

In XSLT 1.0 there is no built-in fucntion to get the current date/time so you can either use an extension fucntion or pass the date as global parameter. Search the forum to see how use global parameters.

hope this helps
Ivan Pedruzzi
Stylus Studio Team


<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:fn="http://www.w3.org/2005/04/xpath-functions"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" version="2.0" method="xml" indent="yes"/>

<xsl:template match="/">
<Cart>
<Param name="time_entered">
<xsl:value-of select="fn:current-dateTime()"/>
</Param>
</Cart>
</xsl:template>

</xsl:stylesheet>

Postnext
Neal  WaltersSubject: Mystery xslt wrapper around my stylesheet?
Author: Neal Walters
Date: 12 May 2005 06:18 PM
I didn't make myself clear. I have a working Stylsheet that actually has NO <xslt:stylesheet> element. Not sure why it works, but it does.

When I try to add the stylesheet element, I get errors on line "3".
This confused me at first, because I look at line 3 and I don't see the error. Finally when I added the <?xml version='1.0' ?> and I still get errors on line 3, I'm thinking that there is a magically built <xslt:stylesheet> statement being built for me that I cannot see?

Does that make any sense at all? So is there an autogenerated non-visible <xslt:stylehseet> somewhere generated or built-in to Stylus Studio?

Thanks,
Neal Walters

Posttop
Ivan PedruzziSubject: Mystery xslt wrapper around my stylesheet?
Author: Ivan Pedruzzi
Date: 12 May 2005 06:33 PM

If the stylesheet has just a template element is not suppose to work.

By any chance did you switch to template mode?
See "Working with Templates" in the Stylus Studio's documentation.

Hope this helps
Ivan

 
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